Drivers pay an average of (mean $690) per year for automobile insurance the distribution of insurance payments is approximately normal with a standard deviation of 110 dollars. What proportion of drivers pay more than 100 dollars per year for insurance?
2 answers
how to get answer to geometric mean problem? data: 25.4, 9, 16, 4.25, 8.11, 19?
Check for typo in your post. If there are no typos, here's how you would proceed.
Standardize:
P(X>100)
=1-P(X≤100)
=1-P(Z≤(100-690)/110)
=1-P(Z≤-5.36)
Look up a probability table for
P(Z≤-5.36) and calculate the answer accordingly.
Standardize:
P(X>100)
=1-P(X≤100)
=1-P(Z≤(100-690)/110)
=1-P(Z≤-5.36)
Look up a probability table for
P(Z≤-5.36) and calculate the answer accordingly.
1 answer