Drive apparent weights of an object of a body of mass and density completual immersed in a fluid

Answer 1

When an object is completely submerged in a fluid, it experiences an apparent loss of weight due to the buoyant force of the fluid on the object.

The buoyant force is equal to the weight of the fluid displaced by the object. Therefore, the apparent weight of the object is equal to its actual weight minus the weight of the fluid displaced.

Mathematically, the buoyant force can be expressed as:

Buoyant force = ρV g

Where:

- ρ = density of fluid
- V = volume of fluid displaced by the object
- g = acceleration due to gravity

The weight of the fluid displaced is equal to the product of its density, its volume, and the acceleration due to gravity:

Weight of fluid displaced = ρVg

Therefore, the apparent weight of the object can be expressed as:

Apparent weight = Actual weight - Weight of fluid displaced
= mg - ρVg

Where:

- m = mass of object
- ρ = density of fluid
- V = volume of fluid displaced by the object
- g = acceleration due to gravity

It is important to note that the apparent weight of the object will be equal to zero if it is floating in the fluid. This occurs when the buoyant force is equal to the weight of the object. If the buoyant force is greater than the weight of the object, it will rise to the surface, while if it is less, it will sink.