DrBobb22
Calcule the concentrations of Cd^+2 , [Cd(CN)4^-2] and CN^- at equilibrium, when 0.42 moles of Cd(NO3)2 dissolves in 1 L of 2.50 M NaCN
Kf for Cd(CN)4^-2
Help!
4 answers
Kf is 7.1 x 10^16
If you answered the question I asked I might be able to help.
I will post again ok?
right. See above for my response.