The median from A goes to the midpoint of BC at (6,3)
Its slope is 3/8, so its equation is
y = 3/8 (x+2)
The bisector of BC also goes through (6,3) with slope -2/5, so its equation is
y-3 = -2/5 (x-6)
draw ABC with vertices A(-2,0)B(8,8),And C (4,-2)
B) draw the median from vertex A. Then,find the equationin slope y-interceptform for this median
c)draw the right bisector of BC. Then,find the equation for this right bisector
2 answers
The