Asked by Sherif
Draw a block and tackle system of pulleys with a velocity ratio of 5 is used to raise a mass of a 25kg through a vertical distance of 40cm at a steady rate.
Answers
Answered by
saleem
Data
VR=5
Work done=25kg
L=40cm
Effort=60N
VR=5
Work done=25kg
L=40cm
Effort=60N
Answered by
HASSAN YUSUF
Draw a block and tackle system of pulley with a velocity ratio of 5. A block tackle, with a velocity ration of 5 used to raise a mass of 25k. through a vertical distance of 40CM a stead by rate if the effort is equal to 60N determine
A= the distance moved by the effort
B= the work done by the effort in lifting the load
C= the loss in energy involved in operating the machine.
A= the distance moved by the effort
B= the work done by the effort in lifting the load
C= the loss in energy involved in operating the machine.
Answer
V.R=De/DL
De=V.r×Dl
=5×40
=200cm=2m
De=V.r×Dl
=5×40
=200cm=2m
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.