Drag and drop the points to graph and solve the system of equations.


y =
2
3​x−2 (blue line)

y=−
1
2​x+5 (red line)
what are the points and the graph only goes up to 8

1 answer

To graph the system of equations given, we will analyze each equation. The equations are:

  1. \( y = \frac{2}{3}x - 2 \) (blue line)
  2. \( y = -\frac{1}{2}x + 5 \) (red line)

Step 1: Determine Points for Each Equation

For the blue line \( y = \frac{2}{3}x - 2 \):

To find points, we can select a few values for \( x \) and calculate \( y \):

  • When \( x = 0 \): \[ y = \frac{2}{3}(0) - 2 = -2 \quad \Rightarrow \text{point } (0, -2) \]

  • When \( x = 3 \): \[ y = \frac{2}{3}(3) - 2 = 0 \quad \Rightarrow \text{point } (3, 0) \]

  • When \( x = 6 \): \[ y = \frac{2}{3}(6) - 2 = 2 \quad \Rightarrow \text{point } (6, 2) \]

For the red line \( y = -\frac{1}{2}x + 5 \):

Again, select values for \( x \):

  • When \( x = 0 \): \[ y = -\frac{1}{2}(0) + 5 = 5 \quad \Rightarrow \text{point } (0, 5) \]

  • When \( x = 6 \): \[ y = -\frac{1}{2}(6) + 5 = 2 \quad \Rightarrow \text{point } (6, 2) \]

  • When \( x = 10 \): \[ y = -\frac{1}{2}(10) + 5 = 0 \quad \Rightarrow \text{point } (10, 0) \quad (\text{but this is outside the graph range: max y = 8}) \]

Summary of Points:

  • Blue line points:

    • (0, -2)
    • (3, 0)
    • (6, 2)
  • Red line points:

    • (0, 5)
    • (6, 2) (This point is also on the blue line.)

Step 2: Finding the Intersection Point

To find the intersection point, we can set the two equations equal to each other:

\[ \frac{2}{3}x - 2 = -\frac{1}{2}x + 5 \]

Solve for \( x \):

Multiply through by 6 (the least common multiple of the denominators):

\[ 6\left(\frac{2}{3}x\right) - 6(2) = 6\left(-\frac{1}{2}x\right) + 6(5) \]

This simplifies to:

\[ 4x - 12 = -3x + 30 \]

Add \( 3x \) to both sides:

\[ 4x + 3x - 12 = 30 \]

Combine:

\[ 7x - 12 = 30 \]

Add 12 to both sides:

\[ 7x = 42 \]

Divide by 7:

\[ x = 6 \]

Step 3: Substitute for \( y \):

Plug \( x = 6 \) back into either equation (using the red line):

\[ y = -\frac{1}{2}(6) + 5 = -3 + 5 = 2 \]

Solution of the System of Equations:

The solution to the system, or the intersection point, is \( (6, 2) \).

Sketching the Graph:

  • The blue line passes through (0, -2), (3, 0), and (6, 2).
  • The red line passes through (0, 5), (6, 2).
  • Both lines intersect at (6, 2).

Final Summary:

Intersection Point: \( (6, 2) \)

You can now take these points to graph the lines on your graph paper, ensuring your graph's y-values do not exceed 8.