Drag and drop Solve the following:(2 points)

Question

ax+15=44 (Response Area)

ax−44<15 (Response Area)

OPTIONS FOR THE "RESPONSE AREAS" X < 59/a, X = 59/a, x < 59a, x = 29a, x < 29/a, x = 59a, x < 29a, x = 29/a

Answer 1

To solve the given equations and inequalities, let's start with them one by one.

1. Equation: \( ax + 15 = 44 \)

To solve for \( x \): \[ ax = 44 - 15 \] \[ ax = 29 \] \[ x = \frac{29}{a} \] So the solution for the equation is \( x = \frac{29}{a} \).

2. Inequality: \( ax - 44 < 15 \)

To solve for \( x \): \[ ax < 15 + 44 \] \[ ax < 59 \] Dividing both sides by \( a \) (assuming \( a > 0 \)): \[ x < \frac{59}{a} \] If \( a < 0 \), the inequality would flip: \[ x > \frac{59}{a} \]

For the provided options, assuming \( a > 0 \), we have:

• From the equation: \( x = \frac{29}{a} \)
• From the inequality: \( x < \frac{59}{a} \)

Thus, the appropriate assignments to the response areas would be:

• Equation: \( x = \frac{29}{a} \)
• Inequality: \( x < \frac{59}{a} \)

You can drag and drop these solutions into the corresponding response areas.