To analyze the situation described in the equation \( m + 20g = 640 \), we can rewrite this to express \( g \) in terms of \( m \):
\[ 20g = 640 - m \] \[ g = \frac{640 - m}{20} \]
This function indicates that the remaining amount of gasoline \( g \) is dependent on the number of miles \( m \) traveled.
- Find the Constraints:
- Since \( g \) represents the gallons of gasoline remaining, it cannot be negative. Therefore, we need \( g \geq 0 \).
- Setting \( g = 0 \) in our equation gives us:
\[ 0 = \frac{640 - m}{20} \]
Multiplying both sides by 20 results in:
\[ 640 - m = 0 \implies m = 640 \]
So the maximum distance \( m \) that can be traveled with a full tank without running out of gas is 640 miles.
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Minimum Value of \( m \):
- The minimum distance that can be traveled is \( m = 0 \).
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Determine the Values of \( g \):
- At \( m = 0 \): \[ g = \frac{640 - 0}{20} = \frac{640}{20} = 32 \]
- At \( m = 640 \): \[ g = \frac{640 - 640}{20} = 0 \]
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Range of Function:
- Therefore, as \( m \) varies from 0 to 640, \( g \) will vary from 32 gallons (when \( m = 0 \)) to 0 gallons (when \( m = 640 \)).
- Thus, the range of the function in this context is:
\[ g \in [0, 32] \]
In conclusion, the completed range of values for gasoline remaining \( g \) as a function of miles traveled \( m \) in this context is \( g \in [0, 32] \).