If b is betty's age, then Don is b+21
In 5 years their ages will be b+6 and b+27
So,
b+27 = 2(b+6)
Solve for b, then you can get Don's age.
Don is 21 years older than Betty. In six year Don will be twice as old as Betty. How old is each now?
2 answers
Betty is X years old.
Don is X+21 years old.
Six years from now:
Betty: X+6 years old.
Don: (X+21) + 6.
(X+21)+6 = 2(x+6).
X = ?
x+21 = ?
don
; (
Don is X+21 years old.
Six years from now:
Betty: X+6 years old.
Don: (X+21) + 6.
(X+21)+6 = 2(x+6).
X = ?
x+21 = ?
don
; (