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Does this relation define a function? y^2=3x My answer: 3x=y^2|0|3|12|27 y |0|1| 2| 3 y^2=3x is a function because the coordina...Asked by Sara
Does this relation define a function?
y^2=3x
My answer:
3x=y^2|0|3|12|27
y |0|1| 2| 3
y^2=3x is a function because the coordinates I chose are not duplicated.
y^2=3x
My answer:
3x=y^2|0|3|12|27
y |0|1| 2| 3
y^2=3x is a function because the coordinates I chose are not duplicated.
Answers
Answered by
Damon
y^2 = 3 x
y = + sqrt(3x)
BUT
y = - sqrt (3x)
for example if x = 12
y = sqrt(36) = 6
BUT
y = -sqrt(36) = -6
works
so there are two values of y for every x
NOT a function
y = + sqrt(3x)
BUT
y = - sqrt (3x)
for example if x = 12
y = sqrt(36) = 6
BUT
y = -sqrt(36) = -6
works
so there are two values of y for every x
NOT a function
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