To analyze the system of equations \( x + y = 2 \) and \( -x + y = 7 \):
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Determine the slopes of the lines:
- For the equation \( x + y = 2 \), we can rewrite it in slope-intercept form \( y = -x + 2 \). The slope here is -1.
- For the equation \( -x + y = 7 \), we can rewrite it in slope-intercept form \( y = x + 7 \). The slope here is 1.
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Compare the slopes:
- The slopes of the two lines are -1 and 1. Since they are different, the lines will intersect.
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Find the intersection point (optional):
- Set the two equations equal to each other for the intersection: \[ -x + 2 = x + 7 \] Combine like terms: \[ 2 - 7 = x + x \implies -5 = 2x \implies x = -\frac{5}{2} \] Substitute \( x \) back into one of the equations to find \( y \): \[ y = -(-\frac{5}{2}) + 7 = \frac{5}{2} + 7 = \frac{5}{2} + \frac{14}{2} = \frac{19}{2} \] So the point of intersection is \( \left(-\frac{5}{2}, \frac{19}{2}\right) \).
Conclusion:
- The lines represented by the equations \( x + y = 2 \) and \( -x + y = 7 \) are not parallel; they intersect at the point \( \left(-\frac{5}{2}, \frac{19}{2}\right) \).
- Therefore, the correct response is: "Both graphs are correct. The lines should intersect."