Asked by M, S, E,
Does the following infinite geometric series diverge or converge? Explain.
1/5 + 1/25 + 1/125 + 1/625
A) It diverges; it has a sum.
B) It converges; it has a sum.
C) It diverges; it does not have a sum.
D) It converges; it does not have a sum.
I am pretty sure that it is divergent. I am only confused by the part of it having a sum. How do I know when a geometric series has a sum.
1/5 + 1/25 + 1/125 + 1/625
A) It diverges; it has a sum.
B) It converges; it has a sum.
C) It diverges; it does not have a sum.
D) It converges; it does not have a sum.
I am pretty sure that it is divergent. I am only confused by the part of it having a sum. How do I know when a geometric series has a sum.
Answers
Answered by
Reiny
Notice that is simply a geometric series, where
a = 1/5, r = 1/5
since Sum(all terms) = a/(1-r)
= (1/5)/(4/5)
= 1/4 , it clearly converges
What made you think it diverges?
What have you studied about diverging and converging series?
( simply adding the first 4 already gives us .2496 )
a = 1/5, r = 1/5
since Sum(all terms) = a/(1-r)
= (1/5)/(4/5)
= 1/4 , it clearly converges
What made you think it diverges?
What have you studied about diverging and converging series?
( simply adding the first 4 already gives us .2496 )
Answered by
M, S, E,
I found this formula for it. -1>r>1
Sorry, I meant converge. I went back and looked at the video. They said converge.
Sorry, I meant converge. I went back and looked at the video. They said converge.
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