Confidence interval using proportions:
CI98 = p + or - (2.33)(sqrt of pq/n)
...where + or - 2.33 represents 98% confidence using a z-table.
(q = 1 - p ...and... n = sample size)
I hope this helps.
Does anyone know how to solve these two problems.
Solve the problem. Find the critical value za/2 that corresponds to a degree of condfidence of 98%.
Express the confidence interval in the form of ^p _+E.
0.033<p>0.493
1 answer