d/dx f(x)g(x) =
f(x)g(x)* [g'(x)ln(f(x))+g(x)f'(x)/f(x) ]
Does anyone know how to find the derivative of 3x^ln(2x)?
2 answers
3x^ln(2x) =
3 exp[ln(2x) ln(x)]
The derivative of exp(f(x)) is
exp(f(x)) f'(x)
You can easily prove this using the chain rule.
3 exp[ln(2x) ln(x)]
The derivative of exp(f(x)) is
exp(f(x)) f'(x)
You can easily prove this using the chain rule.