Does anybody know how (M+/- √M^2-4FGr^2/G))/2 equal to 1.85*10^30+/- 1.32*10^30 When M=1.85*10^30,F=5.00*10^25, G=6.67*10^-11 and r=1.5*10^12. I don't know where 1.32*10^30 comes from. Please explain with steps

Answer 1

a x^2 + b x + c = 0

x = [ -b +/- sqrt(b^2-4ac) ] / 2a

so it looks like
a = 1
b = -1.85*10^30
c = Fr^2 = 5*10^25*2.25*10^24 = 11.25*10^49 = 1.125*10^50

looks like a typo, M is half what it needs to be if M/2 = 1.85*10^30

Answer 2

The whole M is 3.70*10^30 but it got dived by 2 so it becomes 1.85*10^30

Answer 3

Now you tell me :)

Answer 4

a x^2 + b x + c = 0

x = [ -b +/- sqrt(b^2-4ac) ] / 2a

so it looks like
a = 1
b = -3.70*10^30
c = Fr^2 = 5*10^25*2.25*10^24 = 11.25*10^49 = 1.125*10^50

now here is a quadratic solver:
https://www.mathsisfun.com/quadratic-equation-solver.html

Answer 5

[ 3.7*10^30 +/-sqrt(13.69*10^60 -4.5*10^50) ]/2

10^60 overwhelms 10^50
[3.7*10^30 +/- 10^30 sqrt(13.69)]/2

[ 3.7 * 10^30 +/- 10^30 (3.7) ]/2

10^30 [ 1.85 +/- 1.85 ]

Answer 6

so I have no idea where 1.32*10^30 comes from

Answer 7

can you explain how to use the quadratic solver stie? the value for b an dc are too large. It give me DNE when I enter them as you show above

Answer 8

yeah,she is right. I have the same problem Damon

Answer 9

Factor that 10^30 out first so you have reasonable numbers