The best thing to do would be to equate the electrostatic force of attraction and the centripetal force.
(m*v^2)/r = k*(e*e/r^2)
Where m = mass of electron
v = velocity
e = charge on electron (and on hydrogen nucleus)
r = radius of orbit
k = 1/4πƐ = 9 * 10^9
Does anybody know how I can find the mass of the electron for this question. I need to find it first to solve for the real one but don't see mass anywhere in the question.I see radiant and speed but no mass The radius of circular electron orbits in the Bohr model of the hydrogen atom are given by (5.29 ✕ 10−11 m)n2, where n is the electron's energy level (see figure below). The speed of the electron in each energy level is (c/137n), where c = 3 ✕ 108 m/s is the speed of light in vacuum.
3 answers
9.11E-31 Kg ... from google
the speeds are not close enough to c to worry about relativistic effects
the speeds are not close enough to c to worry about relativistic effects
Ah, my bad, I thought you had to solve for 'm' in the question.