In the first year, there were x bears in the park.
Second year: x + 42 = 2(x)
Third year: 2(x) + 50 = 3(x)
Solving the system of equations:
x + 42 = 2x
x = 42
2(42) + 50 = 3(42)
84 + 50 = 126
Therefore, there were 42 bears in the park during the first year.
Does 42 bears come apart and second year the total number of bears in the park during the three year third year is 50 right and solve a linear equation to determine how many beers were in the park during year one note that this answer will not be the same as the answer you got in part of me
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