To determine the concavity of the functions \( f(x) \) and \( g(x) \), we need to analyze their second derivatives.
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Function \( f(x) = -x^2 - 15x \):
- First, we find the first derivative: \[ f'(x) = -2x - 15 \]
- Next, we find the second derivative: \[ f''(x) = -2 \]
- Since \( f''(x) = -2 \) is negative for all values of \( x \), the function \( f(x) \) is concave down.
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Function \( g(x) \):
- From the description in the problem, it states that the graph of \( g(x) \) opens upward, has a minimum point, and then increases. This indicates that \( g(x) \) is a parabola that is concave up.
- Therefore, the concavity of \( g(x) \) is upward.
Now we can compare the concavity of \( f(x) \) and \( g(x) \):
- \( f(x) \) is concave down.
- \( g(x) \) is concave up.
From this analysis, we can conclude that the functions do not have the same concavity.
The correct answer is Choice C: No, \( f \) is concave down and \( g \) is concave up.