To solve the compound inequality \(-51 \leq 5x - 1 < 4\) without breaking it up, you can treat it as one entire inequality. We will solve it step by step.
-
Solve the left side of the inequality: \[ -51 \leq 5x - 1 \] Add 1 to both sides: \[ -51 + 1 \leq 5x \] \[ -50 \leq 5x \] Divide by 5: \[ -10 \leq x \quad \text{or} \quad x \geq -10 \]
-
Solve the right side of the inequality: \[ 5x - 1 < 4 \] Add 1 to both sides: \[ 5x < 4 + 1 \] \[ 5x < 5 \] Divide by 5: \[ x < 1 \]
-
Combine the results: From the two parts, we have: \[ -10 \leq x < 1 \] Therefore, the solution to the compound inequality is: \[ -10 \leq x < 1 \]
-
Graph the solution: To graph the solution on the number line:
- Draw a line with numbers from -10 to 1.
- Place a closed dot at -10 (indicating -10 is included).
- Place an open dot at 1 (indicating 1 is not included).
- Shade the region between -10 and 1.
Here's a representation of the graph:
<-----●==================○----->
-10 1
Final Result:
The solution to the inequality \(-51 \leq 5x - 1 < 4\) is: \[ x \in [-10, 1) \]