Ok, your first sentence is given the mols of Fe(II). Did you mean Fe(III) ? I assume so.
Balance the equation.
Fe + H2SO4+H3PO4>>FeSO4.7H20 + where did the phosphate go? Your reaction is incomplete
Do i need a chemical formula to calculate the mols of FeSO4*7H20 when given the mols of Fe(II)?
If so i only know that Fe(III) + H2SO4 + H3PO4 are the reactants, and FeSO4*H2O is the product. Help?
3 answers
the mols for Fe(II) are the same as Fe(III) since the ratio is 1:1.
And that's the problem with the reaction. I don't know what else is made. I was just given those components. I'm assuming it would yeild FsSO4*7H2O + P? But i am unsure.
And that's the problem with the reaction. I don't know what else is made. I was just given those components. I'm assuming it would yeild FsSO4*7H2O + P? But i am unsure.
The only hint I was given was that I use the mols of Fe(II) to find the mols of FeSO4*7H20
1 answer