dividing monomials

Question

(10ab)^2 (2a^4b^30/4da^5b

Answer 1

First, let's simplify each part separately:

(10ab)^2 = 100a^2b^2

(2a^4b^30)/(4da^5b) = (1/2) * a^(-1) * b^29 * d^(-1)

Now, let's divide these two results:

100a^2b^2 / ((1/2) * a^(-1) * b^29 * d^(-1))

= 100 * a^2 * b^2 * 2/a * 1/b^29 * 1/d

= 200a/ d * b^(2-29)

= 200a/d * b^(-27)

Therefore, the final result is: 200a/d * b^(-27)