Let’s go through the division process step by step:
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Divide: 127 ÷ 3
We need to find out how many groups of 3 can fit into 127.
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Write the dividend in expanded form:
127 can be expressed in expanded form as:
- \(100 + 20 + 7\)
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Regroup the hundreds piece into 10 tens:
We can take 100 and break it down into 10 tens:
- \( (100 = 10 \times 10)\)
So now, the new expanded form is:
- \( (10 \times 10) + 20 + 7\)
This gives us \(10 + 2 = 12\) tens (remembering we had 7 single units from before).
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Start the division:
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First, see how many times 3 fits into 12 (from 120):
- \(3 \times 4 = 12\).
- So there are 4 full groups of 3 in 12.
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This accounts for 120.
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Then, 7 minus what we used equals a remainder of 7.
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Now, we can include the leftover 7 units:
- \(3\) fits into \(7\) how many times? That gives \(2\) groups.
- Remaining is \(7 - 6 = 1\).
So, the final quotient is \(42\) with a remainder of \(1\).
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The final answer is: \( \text{Quotient: } 42 \text{ R } 1\)
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Check the answer:
To check:
- Multiply the quotient by the divisor and add the remainder.
- \(42 \times 3 + 1 = 126 + 1 = 127\).
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Conclusion:
Our answer is confirmed, and we have:
- How many groups? 42 R 1.
1 answer