Divide (x^4-y^4) by (x-y).

Need to show work to help me understand.
Also need to answer without parentheses.

Thanks for any and all help with this one!!

3 answers

(x^4-y^4)
= (x^2 - y^2)(x^2 + y^2)
= (x+y)(x-y)(x^2 + y^2)

so (x^4-y^4)÷(x-y)
= (x+y)(x-y)(x^2 + y^2)÷(x-y)
= (x+y)(x^2 + y^2)

expand this if you don't want the brackets.

Hey, thanks for your help.

welcome