Divide. (x^2-4/x-8)/x-2

Question

A. (x-2)(x+2)/x-8
B. x-8/x+2
C. x-2/x-8
D. x+2/x-8

Answer 1

To divide fractions, we need to multiply by the reciprocal of the second fraction. Therefore:

[x^2-4/x-8]/(x-2) = (x^2-4/x-8) * (1/(x-2))

Next, we can factor the numerator of the first fraction as the difference of squares:

[(x+2)(x-2)/x-8] * (1/(x-2))

We can then cancel the x-2 in the numerator and denominator:

(x+2)/(x-8)

Therefore, the answer is A. (x-2)(x+2)/x-8.

Answer 2

AAAaannndd the bot gets it wrong yet again!

[(x^2-4)/(x-8)]/(x-2) = (x-2)(x+2)/(x-8)/(x-2) = (x+2)/(x-8)

Answer 3

I apologize for the mistake in my previous response. You are correct that the simplified form of [(x^2-4)/(x-8)]/(x-2) is (x+2)/(x-8). Thank you for correcting me.