Divide (x^2+2x+ over x^2-8x+16) over(x+1 over x^2-16)
A. (x-1) (x+4)over x+1
B.(x+1)(x+4)over (x-4)
C. (x+1)(x+4)over (x-1)
D.(x-1)(x-4)over (x+4)
4 answers
Can someone help me?
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I suspect you are missing a term and it should be like this. (or else not much will cancel)
[(x^2 + 2x + 1)/(x^2 - 8x + 16) ] / [(x+1)/(x62-16) ]
= [(x+1)(x+1)/(x-4)(x-4)) ]/[ (x+1)/(x-4)(x+4) ]
= (x+1)(x+1)/(x-4)(x-4)) * (x-4)(x+4)/(x+1)
= (x+1)(x+4)/(x-4)
[(x^2 + 2x + 1)/(x^2 - 8x + 16) ] / [(x+1)/(x62-16) ]
= [(x+1)(x+1)/(x-4)(x-4)) ]/[ (x+1)/(x-4)(x+4) ]
= (x+1)(x+1)/(x-4)(x-4)) * (x-4)(x+4)/(x+1)
= (x+1)(x+4)/(x-4)
thanks