Divide.

Question

Write your answer in simplest form.


\[ -\dfrac{6}{7} \div \left(-\dfrac{3}{8}\right) = {?} \]

Answer 1

To divide fractions, we multiply the first fraction by the reciprocal (flipped) of the second fraction.

So, we have:
\[ -\dfrac{6}{7} \div \left(-\dfrac{3}{8}\right) = -\dfrac{6}{7} \times \dfrac{-8}{3} \]

We can simplify this expression by canceling out common factors.
The 6 in the numerator and the 8 in the denominator can both be divided by 2:
\[ -\dfrac{6}{7} \times \dfrac{-8}{3} = -\dfrac{3}{7} \times \dfrac{-4}{1} \]

Now, we can multiply:
\[ -\dfrac{3}{7} \times \dfrac{-4}{1} = \dfrac{12}{7} \]

Therefore, \[ -\dfrac{6}{7} \div \left(-\dfrac{3}{8}\right) = \dfrac{12}{7} \]

Answer 2

wrong. you are really screwing with my grades.

Answer 3

Apologies for the mistake, let's correct it. To divide fractions, we multiply the first fraction by the reciprocal (flipped) of the second fraction.

So, we have:

\[ -\dfrac{6}{7} \div \left(-\dfrac{3}{8}\right) = -\dfrac{6}{7} \times \left(-\dfrac{8}{3}\right) \]

Multiplying the numerators and denominators, we get:

\[ -\dfrac{6 \times (-8)}{7 \times 3} = \dfrac{48}{21} \]

Next, we can simplify this fraction by dividing both the numerator and denominator by their greatest common divisor, which is 3:

\[ \dfrac{48}{21} = \dfrac{16}{7} \]

Therefore, \[ -\dfrac{6}{7} \div \left(-\dfrac{3}{8}\right) = \dfrac{16}{7} \]