To divide the polynomial \( 12x^2 + 2x - 9 \) by \( 4x - 2 \), let's perform polynomial long division.
Step 1: Set up the division.
Dividing \( 12x^2 + 2x - 9 \) by \( 4x - 2 \).
Step 2: Divide the leading term.
- Divide \( 12x^2 \) by \( 4x \) to get \( 3x \).
Step 3: Multiply and subtract.
- Multiply \( 3x \) by \( 4x - 2 \): \[ 3x(4x - 2) = 12x^2 - 6x \]
- Now subtract this from \( 12x^2 + 2x - 9 \): \[ (12x^2 + 2x - 9) - (12x^2 - 6x) = (2x + 6x) - 9 = 8x - 9 \]
Step 4: Divide the leading term again.
- Now divide \( 8x \) by \( 4x \) to get \( 2 \).
Step 5: Multiply and subtract again.
- Multiply \( 2 \) by \( 4x - 2 \): \[ 2(4x - 2) = 8x - 4 \]
- Now subtract this from \( 8x - 9 \): \[ (8x - 9) - (8x - 4) = -9 + 4 = -5 \]
After performing the long division, we find:
- Quotient: \( 3x + 2 \)
- Remainder: \( -5 \)
Step 6: Express the result. Thus, we can express the original polynomial as: \[ 12x^2 + 2x - 9 = (4x - 2)(3x + 2) - 5 \]
The correct answer is: \[ 12x^2 + 2x - 9 = (4x - 2)(3x + 2) - 5 \]
So, the final response is: 12x² + 2x - 9 = (4x - 2)(3x + 2) - 5.