when dividing by a fraction, just invert and multiply. So,
#1
3a^4b/2a^2c^3 * 8c^4/12a^2c
= 3*8/12 a^4/a^2 b c/c^3
...
#2
x^2+4x-5 = (x+5)(x-1)
x^2-25 = (x+5)(x-5)
So, you just have
(x+5)(x-1) / 3(x-1) * 1 / (x+5)(x-5)
= (x+5)(x-1) / 3(x+5)(x-1)(x-5)
= ...
Divide. Simplify your answer.
1. 3a^4b/2a^2c^3 ÷ 12a^2c/8c^4
A: ?
2. x^2 + 4x - 5/3x - 3 ÷ (xC^2 - 25)
A: ?
6 answers
1. A: ?
2. A: 1/3x-15
2. A: 1/3x-15
Am I correct?
I still don't know the answer to #1.
I still don't know the answer to #1.
Hmmm. How about
2a^2b / c^2
2a^2b / c^2
Is this the answer to #1? Or am I incorrect?
yes,
#1 = 2a^2b/c^2
#2 = 1/(3x-15)
#1 = 2a^2b/c^2
#2 = 1/(3x-15)