To find the width of the park, you can divide the area by the length:
\[ \text{Width} = \frac{\text{Area}}{\text{Length}} = \frac{1.36 \times 10^8 \text{ ft}^2}{1.6 \times 10^4 \text{ ft}} \]
Now, divide the coefficients and the powers of ten separately:
-
Coefficients: \[ \frac{1.36}{1.6} = 0.85 \]
-
Powers of ten: \[ \frac{10^8}{10^4} = 10^{8-4} = 10^4 \]
Now, combine the two results: \[ \text{Width} = 0.85 \times 10^4 \]
To express \(0.85\) in scientific notation, it can be rewritten as \(8.5 \times 10^{-1}\), so: \[ \text{Width} = 8.5 \times 10^{-1} \times 10^4 = 8.5 \times 10^{4 - 1} = 8.5 \times 10^3 \]
Thus, the width of the park is: \[ \boxed{8.5 \times 10^3 \text{ ft}} \]
So the correct answer is: 8.5×103 ft.