To find the width of the park, we need to divide the area by the length. The area is given in scientific notation, as 1.36 x 10^8 ft^2, and the length is given as 1.6 x 10^4 ft.
To divide these values, we divide the coefficients (1.36 / 1.6) and subtract the exponents (10^8 / 10^4).
1.36 / 1.6 = 0.85, and 10^8 / 10^4 = 10^(8-4) = 10^4.
Therefore, the width of the park in scientific notation is 0.85 x 10^4 ft.
Rewriting this in proper scientific notation:
0.85 x 10^4 ft = 8.5 x 10^3 ft.
So the width of the park is 8.5 x 10^3 ft.
Divide in Scientific Notation Quick Check
1 of 5
Item 1
Item 2
Item 3
A rectangular park has an area of 1.36 x 108 ft2. The length of the park is 1.6 x 104 ft. Divide the area by the length to find the width of the park. (1 point)
8.5 x 10^5 ft.
O 8.5 x 10^3 ft.
8.5 x 10^4 ft.
O 8.5 x 10^2 ft.
3 answers
Sorry i ment, Divide in Scientific Notation Quick Check
1 of 5
Item 1
Item 2
Item 3
A rectangular park has an area of 1.36 x 108 ft2. The length of the park is 1.6 x 104 ft. Divide the area by the length to find the width of the park. (1 point)
8.5 x 105 ft.
O 8.5 x 103 ft.
Item 4
8.5 x 10 ft.
O 8.5 x 102 ft.
Hem &
Divide in Scientific Notation Quick Check
1 of 5
Item 1
Item 2
Item 3
A rectangular park has an area of 1.36 x 10^8 ft^2. The length of the park is 1.6 x 10^4 ft. Divide the area by the length to find the width of the park. (1 point)
8.5 x 10^5 ft.
O 8.5 x 10^3 ft.
8.5 x 10^4ft.
O 8.5 x 10^2 ft.
1 of 5
Item 1
Item 2
Item 3
A rectangular park has an area of 1.36 x 108 ft2. The length of the park is 1.6 x 104 ft. Divide the area by the length to find the width of the park. (1 point)
8.5 x 105 ft.
O 8.5 x 103 ft.
Item 4
8.5 x 10 ft.
O 8.5 x 102 ft.
Hem &
Divide in Scientific Notation Quick Check
1 of 5
Item 1
Item 2
Item 3
A rectangular park has an area of 1.36 x 10^8 ft^2. The length of the park is 1.6 x 10^4 ft. Divide the area by the length to find the width of the park. (1 point)
8.5 x 10^5 ft.
O 8.5 x 10^3 ft.
8.5 x 10^4ft.
O 8.5 x 10^2 ft.
To find the width of the park, we need to divide the area by the length. The area is given in scientific notation as 1.36 x 10^8 ft^2, and the length is given as 1.6 x 10^4 ft.
To divide these values, we divide the coefficients (1.36 / 1.6) and subtract the exponents (10^8 / 10^4).
1.36 / 1.6 = 0.85, and 10^8 / 10^4 = 10^(8-4) = 10^4.
Therefore, the width of the park in scientific notation is 0.85 x 10^4 ft.
Rewriting this in proper scientific notation:
0.85 x 10^4 ft = 8.5 x 10^3 ft.
So the width of the park is 8.5 x 10^3 ft.
The correct answer to the question is:
O 8.5 x 10^3 ft.
To divide these values, we divide the coefficients (1.36 / 1.6) and subtract the exponents (10^8 / 10^4).
1.36 / 1.6 = 0.85, and 10^8 / 10^4 = 10^(8-4) = 10^4.
Therefore, the width of the park in scientific notation is 0.85 x 10^4 ft.
Rewriting this in proper scientific notation:
0.85 x 10^4 ft = 8.5 x 10^3 ft.
So the width of the park is 8.5 x 10^3 ft.
The correct answer to the question is:
O 8.5 x 10^3 ft.
1 answer