To find the quotient of the mixed numbers \(4 \frac{1}{3}\) and \(-1 \frac{1}{5}\), we first convert them to improper fractions.
- Convert \(4 \frac{1}{3}\):
\[
4 \frac{1}{3} = \frac{4 \times 3 + 1}{3} = \frac{12 + 1}{3} = \frac{13}{3}
\]
- Convert \(-1 \frac{1}{5}\):
\[
-1 \frac{1}{5} = -\left(\frac{1 \times 5 + 1}{5}\right) = -\left(\frac{5 + 1}{5}\right) = -\frac{6}{5}
\]
Now, we divide the two improper fractions:
\[
\frac{13}{3} \div -\frac{6}{5}
\]
To divide by a fraction, we multiply by its reciprocal:
\[
\frac{13}{3} \times -\frac{5}{6}
\]
Now, we multiply the fractions:
\[
\frac{13 \times -5}{3 \times 6} = \frac{-65}{18}
\]
Next, let's convert \(-\frac{65}{18}\) back to a mixed number:
- Divide \(65\) by \(18\):
\[
65 \div 18 = 3 \quad (\text{with a remainder of } 11)
\]
So, we can write:
\[
-\frac{65}{18} = -3 \frac{11}{18}
\]
The correct answer is:
C \(-3 \frac{11}{18}\)