Divide -3x^(3)-4x^(2)+4x+3 by x-2.

Answer 1

To divide \( -3x^3 -4x^2 +4x +3 \) by \( x-2 \), we can use long division.

_______________________
x - 2 | -3x^3 - 4x^2 + 4x + 3
-3x^3 + 6x^2
_____________
- 10x^2 + 4x + 3
- 10x^2 + 20x
_____________
- 16x + 3
- 16x + 32
_____________
-29

Hence, the quotient is \( -3x^2 + 6x - 16 \) and the remainder is -29.