Distinguish between real and apparent cubic expansivity of a liquid.A glass bottle full of Mercury has mass 500g an being heated through 35°c,2,43g of Mercury are expelled. Calculate the mass of Mercury remaining in the bottle (cubic expansivity of Mercury) is 1.8×10-4 per k, linear expansivity of glass Is 8.0×10-6 per k
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Mg=500g
^(temperature) =35°C.
mHg expelled=2.43g
mHg remaining =?
Cubic expansivity of Mercury= 1.8×10-4K-1.
Linear expansivity of glass=8.0×10-6K-1
Apparent cubic expansivity = mass expelled÷ mass remaining × temperature rise.
Real cubic expansivity = apparent cubic expansivity + cubic expansivity of glass.
Apparent cubic expansivity + 3× linear expansivity of glass
Apparent cubic expansivity = real cubic expansivity - 3× linear expansivity of glass.
Apparent cubic expansivity= 1.8× 10-4 _ 3(8.0×10-6).
1.8×10-4_24×10-6
=0.00018_0.000024.
Apparent cubic expansivity=0.000156K-1
0.000156K-1=2.43÷mass remaining ×35
Mass remaining =2.43÷0.000156 ×35
Mass remaining = 445.05g
^(temperature) =35°C.
mHg expelled=2.43g
mHg remaining =?
Cubic expansivity of Mercury= 1.8×10-4K-1.
Linear expansivity of glass=8.0×10-6K-1
Apparent cubic expansivity = mass expelled÷ mass remaining × temperature rise.
Real cubic expansivity = apparent cubic expansivity + cubic expansivity of glass.
Apparent cubic expansivity + 3× linear expansivity of glass
Apparent cubic expansivity = real cubic expansivity - 3× linear expansivity of glass.
Apparent cubic expansivity= 1.8× 10-4 _ 3(8.0×10-6).
1.8×10-4_24×10-6
=0.00018_0.000024.
Apparent cubic expansivity=0.000156K-1
0.000156K-1=2.43÷mass remaining ×35
Mass remaining =2.43÷0.000156 ×35
Mass remaining = 445.05g