Distance

(ft.) Speed
(ft./sec.)
0 0
1 6.33
2 8.95
3 10.96
4 12.66
The table represents the speed of a free-falling object as a function of distance. Use technology to create a square root function that models this data. Round values to the nearest hundredth.

(1 point)
In the square root function that represents the table of data is s(x)=
𝑠
(
𝑥
)
=
x−−√
𝑥
.

1 answer

To create a square root function that models the speed \( s(x) \) as a function of the distance \( x \) from the provided data, we can assume a relationship of the form:

\[ s(x) = k \sqrt{x} \]

where \( k \) is a constant that we will determine using the data from the table.

Let's use the given data points to find the value of \( k \):

  1. When \( x = 0 \), \( s(0) = 0 \) implies it fits the function.
  2. When \( x = 1 \), \( s(1) = 6.33 \): \[ 6.33 = k \sqrt{1} \quad \Rightarrow \quad k = 6.33 \]
  3. When \( x = 2 \), \( s(2) = 8.95 \): \[ 8.95 = k \sqrt{2} \quad \Rightarrow \quad k = \frac{8.95}{\sqrt{2}} \approx 6.34 \]
  4. When \( x = 3 \), \( s(3) = 10.96 \): \[ 10.96 = k \sqrt{3} \quad \Rightarrow \quad k = \frac{10.96}{\sqrt{3}} \approx 6.34 \]
  5. When \( x = 4 \), \( s(4) = 12.66 \): \[ 12.66 = k \sqrt{4} \quad \Rightarrow \quad k = \frac{12.66}{2} = 6.33 \]

From the calculations, we find that \( k \) is consistently around 6.33 to 6.34.

Thus, we can conclude that the square root function that models the data can be expressed as:

\[ s(x) \approx 6.33 \sqrt{x} \]

So, the function representation is:

\[ s(x) = 6.33 \sqrt{x} \]

Rounding to the nearest hundredth gives:

\[ s(x) = 6.33 \sqrt{x} \]