Distance and the Pythagorean Theorem Quick Check%0D%0A4 of 54 of 5 Items%0D%0A%0D%0A%0D%0A%0D%0A%0D%0AQuestion%0D%0AUse the image to answer the question.%0D%0A%0D%0A%0D%0A%0D%0AApply the Pythagorean Theorem to find the length between the two points. Round your answer to the nearest hundredth, if necessary.%0D%0A%0D%0A(1 point)%0D%0AResponses%0D%0A%0D%0A5.57%0D%0A5.57%0D%0A%0D%0A41%0D%0A41%0D%0A%0D%0A6:40%0D%0A6:40%0D%0A%0D%0A9
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The given information is incomplete and does not provide sufficient details or an image to accurately answer the question. Please provide the necessary information or image for a proper response.
one point is at x-2 y-1 and the other point is at x2 y4
To find the distance between the two points using the Pythagorean Theorem, we need to determine the lengths of the horizontal and vertical sides of the right triangle formed by the two points.
The horizontal side can be found by subtracting the x-coordinates: 2 - (-2) = 4.
The vertical side can be found by subtracting the y-coordinates: 4 - (-1) = 5.
Now we can apply the Pythagorean Theorem:
c^2 = a^2 + b^2,
where c is the hypotenuse (the distance between the two points) and a and b are the lengths of the sides.
Substituting the values into the equation:
c^2 = 4^2 + 5^2,
c^2 = 16 + 25,
c^2 = 41.
Taking the square root of both sides, we find:
c = √41.
Rounding to the nearest hundredth, the length between the two points is approximately 6.40.
The horizontal side can be found by subtracting the x-coordinates: 2 - (-2) = 4.
The vertical side can be found by subtracting the y-coordinates: 4 - (-1) = 5.
Now we can apply the Pythagorean Theorem:
c^2 = a^2 + b^2,
where c is the hypotenuse (the distance between the two points) and a and b are the lengths of the sides.
Substituting the values into the equation:
c^2 = 4^2 + 5^2,
c^2 = 16 + 25,
c^2 = 41.
Taking the square root of both sides, we find:
c = √41.
Rounding to the nearest hundredth, the length between the two points is approximately 6.40.
1 answer