To tackle the questions based on the given data of disposable income, let's break down each part.
Part 1
We need to evaluate whether the data can be fitted exactly by a linear model. To determine this, we need to analyze the first differences of the income data provided.
The first differences can be calculated by subtracting the previous year's income from the current year's income.
Calculating the first differences:
\[ \begin{align*} 2015 - 2010 & : 11.028 - 10.916 = 0.112 \ 2020 - 2015 & : 12.545 - 11.028 = 1.517 \ 2025 - 2020 & : 14.688 - 12.545 = 2.143 \ 2030 - 2025 & : 15.132 - 14.688 = 0.444 \ 2035 - 2030 & : 17.651 - 15.132 = 2.519 \ 2040 - 2035 & : 19.564 - 17.651 = 1.913 \ \end{align*} \]
Since the first differences are not constant, the correct answer is: B. No. The first differences are not constant for uniform inputs.
Part 2
Next, we will find a linear model \( y = mx + b \), where \( x \) is the number of years after 2000, and \( y \) is the total disposable income in billions of dollars.
We can use two points from the data to determine the slope \( m \) and y-intercept \( b \). Let's use the years 2010 (x=10, y=10.916) and 2040 (x=40, y=19.564):
Calculating the slope \( m \): \[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{19.564 - 10.916}{40 - 10} = \frac{8.648}{30} \approx 0.288 \]
Calculating the y-intercept \( b \): Using the point (10, 10.916): \[ y = mx + b \implies 10.916 = 0.288(10) + b \implies 10.916 = 2.88 + b \implies b \approx 10.916 - 2.88 \approx 8.036 \]
The linear model can be written as: \[ y = 0.288x + 8.036 \]
Rounded to three decimal places, it is: \[ y = 0.288x + 8.036 \]
Part 3
Now we use the linear model to predict the total disposable income in 2023 (which is 23 years after 2000, or \( x = 23 \)):
\[ y = 0.288(23) + 8.036 \]
Calculating: \[ y \approx 0.288 \times 23 + 8.036 \approx 6.624 + 8.036 \approx 14.660 \]
So, the predicted total disposable income in 2023 is approximately: \[ \boxed{14.660 \text{ billion dollars}} \]
In summary:
- Part 1: B. No. The first differences are not constant for uniform inputs.
- Part 2: \( y = 0.288x + 8.036 \)
- Part 3: \( 14.660 \) billion dollars in 2023.