a. D = 4.58 + 6.25i - 8.65 - 1.84i =
-4.07 + 4.41i, Q2
D = sqrt(4.07^2+4.41^2) km.
b. Tan A = Y/X = 4.41/-4.07 = -1.08354
A = -47.3o = 47.3o N. of W.
Displacement vector points due east and has a magnitude of 4.58 km. Displacement vector points due north and has a magnitude of 6.25 km. Displacement vector points due west and has a magnitude of 8.65 km. Displacement vector points due south and has a magnitude of 1.84 km. Find (a) the magnitude of the resultant vector + + + , and (b) its direction as a positive angle relative to due west.
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