Let's solve each of the quadratic equations:
1. (x + 3)(x - 1) = 0
To find the roots, set each factor to zero:
- \( x + 3 = 0 \) → \( x = -3 \)
- \( x - 1 = 0 \) → \( x = 1 \)
So, the answers are:
- x = -3 and x = 1
2. (15x - 5)(7 + x) = 0
Set each factor to zero:
- \( 15x - 5 = 0 \) → \( 15x = 5 \) → \( x = \frac{5}{15} = \frac{1}{3} \)
- \( 7 + x = 0 \) → \( x = -7 \)
So, the answers are:
- x = -7 and x = \( \frac{1}{3} \)
3. (13x - 2)(x - 34) = 0
Set each factor to zero:
- \( 13x - 2 = 0 \) → \( 13x = 2 \) → \( x = \frac{2}{13} \)
- \( x - 34 = 0 \) → \( x = 34 \)
So, the answers are:
- x = \( \frac{2}{13} \) and x = 34
4. 30 = x² + 13x
Rearrange this into standard form:
- \( x² + 13x - 30 = 0 \)
Now, factor: We need two numbers that multiply to -30 and add to 13. The numbers are 15 and -2. So we can write:
- \( (x + 15)(x - 2) = 0 \)
Set each factor to zero:
- \( x + 15 = 0 \) → \( x = -15 \)
- \( x - 2 = 0 \) → \( x = 2 \)
So, the answers are:
- x = -15 and x = 2
Summary of Answers
- x = -3 and x = 1
- x = -7 and x = \( \frac{1}{3} \)
- x = \( \frac{2}{13} \) and x = 34
- x = -15 and x = 2
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