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Solve the following equations by inspection. There are two real solutions. Enter the lesser number first.

(1 point)
1) x2=36
The solutions are:
and

2) x2=81
The solutions are:
and

3) x2=4
The solutions are:
and

4) x2=49
The solutions are:
and

5) x2=25
The solutions are:
and

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Answer 1

To solve the equations by inspection, we need to determine the square roots of the numbers provided. For every equation of the form \( x^2 = a \), the solutions are \( x = \sqrt{a} \) and \( x = -\sqrt{a} \).

1. For \( x^2 = 36 \):

   • Solutions are \( x = 6 \) and \( x = -6 \).
   • The solutions are: -6 and 6.

2. For \( x^2 = 81 \):

   • Solutions are \( x = 9 \) and \( x = -9 \).
   • The solutions are: -9 and 9.

3. For \( x^2 = 4 \):

   • Solutions are \( x = 2 \) and \( x = -2 \).
   • The solutions are: -2 and 2.

4. For \( x^2 = 49 \):

   • Solutions are \( x = 7 \) and \( x = -7 \).
   • The solutions are: -7 and 7.

5. For \( x^2 = 25 \):

   • Solutions are \( x = 5 \) and \( x = -5 \).
   • The solutions are: -5 and 5.

Now you have all the solutions listed. Make sure to check your answers!