To solve the questions related to the function \( f(x) = x^2 - 3x + 2 \), let's calculate the required values.
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Graph f(x) = x² - 3x + 2: You can graph this function using Desmos or any graphing calculator. The graph of this quadratic function is a parabola that opens upwards.
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f(0): \[ f(0) = 0^2 - 3(0) + 2 = 2 \] So, \( f(0) = 2 \).
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f(1): \[ f(1) = 1^2 - 3(1) + 2 = 1 - 3 + 2 = 0 \] So, \( f(1) = 0 \).
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f(2): \[ f(2) = 2^2 - 3(2) + 2 = 4 - 6 + 2 = 0 \] So, \( f(2) = 0 \).
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The y-intercept: The y-intercept occurs when \( x = 0 \), which we have already calculated. The coordinates of the y-intercept are \( (0, f(0)) = (0, 2) \). So, the y-intercept is \( (0, 2) \).
Here are the answers in order:
- \( f(0) = 2 \)
- \( f(1) = 0 \)
- \( f(2) = 0 \)
- The y-intercept is \( (0, 2) \)