rate = k*(N2O5)^1
moles N2O5 = g/molar mass = 3g/108 = 0.0278
M N2O5 = mols/L = 0.0278 moles/1L = 0.0278M
rate = 8.2E-3* 0.0278 M = ? M/s
Dinitrogen pentoxide, N2O5, decomposes by a first-order reaction. What is the initial rate
for the decomposition of N2O5, when 3 g of N2O5 is confined in a 1 l container and heated
to 65°C? Note that the rate constant for this decomposition process is 8.2×10-3s-1 at 65°C.
1 answer
1 answer