Dimitri bought a cylindrical clay flowerpot that holds about 4 ft^3 of dry soil. The radius of the pot is 9 inches. What is the height of the flowerpot to the nearest tenth of a foot?

Answer 1

To find the height of the flowerpot, we can use the formula for the volume of a cylinder:

V = πr^2h

Given:
V = 4 ft^3
r = 9 inches = 0.75 feet

Now we can plug in the values and solve for h:

4 = π(0.75)^2h
4 = π(0.5625)h
4 = 1.765h
h = 4 / 1.765
h ≈ 2.26 feet

Therefore, the height of the flowerpot is approximately 2.3 feet.