Dilating Figures Quick Check 4 of 54 of 5 Items Question Triangle XYZ is drawn on a coordinate plane with vertices X(0,4) , Y(2,0) , and Z(4,7) . If you dilate the triangle to form triangle X′Y′Z′ using a magnitude of 12 and a center of dilation at (4,7) , what are the coordinate points of the new vertices?(1 point) Responses X′(2,5.5), Y′(3,3.5), Z′(4,7) upper X prime left parenthesis 2 comma 5.5 right parenthesis , upper Y prime left parenthesis 3 comma 3.5 right parenthesis , upper Z prime left parenthesis 4 comma 7 right parenthesis X′(−4,1), Y′(0,−7), Z′(4,7) upper X prime left parenthesis negative 4 comma 1 right parenthesis , upper Y prime left parenthesis 0 comma negative 7 right parenthesis , upper Z prime left parenthesis 4 comma 7 right parenthesis X′(4,11), Y′(6,7), Z′(8,14) upper X prime left parenthesis negative 4 comma 11 right parenthesis , upper Y prime left parenthesis 6 comma 7 right parenthesis , upper Z prime left parenthesis 8 comma 14 right parenthesis X′(−4,−3), Y′(−2,−7), Z′(0,0) upper X prime left parenthesis negative 4 comma negative 3 right parenthesis , upper Y prime left parenthesis negative 2 comma negative 7 right parenthesis , upper Z prime left parenthesis 0 comma 0 right parenthesis Skip to navigation page 16 of 16 Formula keypad has been closed. Press Control + Backslash to open it again.Formula keypad has been closed. Press Control + Backslash to open it again.Formula keypad has been closed. Press Control + Backslash to open it again.Formula keypad has been closed. Press Control + Backslash to open it again.Formula keypad has been closed. Press Control + Backslash to open it again.

1 answer

To find the coordinates of the new vertices of triangle X′Y′Z′ after dilating triangle XYZ, we need to use the formula for dilation given a center of dilation.

The formula for finding the coordinates \( (x', y') \) of a point \( (x, y) \) after dilation with a center of dilation at \( (a, b) \) and a magnification factor \( k \) is:

\[ x' = a + k(x - a) \] \[ y' = b + k(y - b) \]

In this case, the center of dilation is \( (4, 7) \) and the magnitude of dilation is \( 12 \).

Let's calculate the new coordinates for each vertex one by one.

For Vertex X(0, 4):

  • \( a = 4 \), \( b = 7 \), \( k = 12 \)
  • \( x' = 4 + 12(0 - 4) = 4 + 12(-4) = 4 - 48 = -44 \)
  • \( y' = 7 + 12(4 - 7) = 7 + 12(-3) = 7 - 36 = -29 \)

So, \( X'(-44, -29) \).

For Vertex Y(2, 0):

  • \( x' = 4 + 12(2 - 4) = 4 + 12(-2) = 4 - 24 = -20 \)
  • \( y' = 7 + 12(0 - 7) = 7 + 12(-7) = 7 - 84 = -77 \)

So, \( Y'(-20, -77) \).

For Vertex Z(4, 7):

Since this vertex is the center of dilation, the coordinates will not change.

  • \( Z' = (4, 7) \).

Putting it all together:

  • \( X'(-44, -29) \)
  • \( Y'(-20, -77) \)
  • \( Z'(4, 7) \)

However, based on the given responses, none of them correctly reflect the calculated results. It seems there may have been an error in the response choices provided or perhaps a misunderstanding in the magnitude or center of dilation. Please double-check the given values or the options. If you provide the correct values/options or clarify the parameters, I’d be glad to help re-evaluate.