To express the total storage capacity of an 8 GB USB flash drive in bytes, we start with the conversion factor that 1 GB equals \(2^{30}\) bytes.
Given that: \[ 1 \text{ GB} = 2^{30} \text{ bytes} \]
We can calculate the total storage of 8 GB in bytes as follows:
\[ 8 \text{ GB} = 8 \times 2^{30} \text{ bytes} \]
Now, we can express 8 as \(2^3\):
\[ 8 \times 2^{30} = 2^3 \times 2^{30} = 2^{3+30} = 2^{33} \text{ bytes} \]
Next, we need to calculate \(2^{33}\) in base 10. To do this:
\[ 2^{10} = 1024 \]
To find \(2^{30}\), we calculate:
\[ (2^{10})^3 = 1024^3 \]
Calculating \(1024^3\):
\[ 1024 \times 1024 = 1,048,576 \quad (this \ is \ 2^{20}) \]
Now multiplying \(1,048,576\) by \(1024\):
\[ 1,048,576 \times 1024 = 1,073,741,824 \quad (this \ is \ 2^{30}) \]
Finally, we compute \(2^{33}\):
\[ 2^{33} = 2^{30} \times 2^3 = 1,073,741,824 \times 8 = 8,589,934,592 \]
Thus, the total storage capacity of an 8 GB USB flash drive in bytes is:
\[ \text{Total Storage Capacity} = 8,589,934,592 \text{ bytes} \]