y = sin(sin x)
y' = cos (sin x) * cos x
Differntiate
sin(sinx) using the product rule
3 answers
how can you explain the steps and formula
Let z = sin x
then we have
d/dx [ sin z }
which is
cos z * dz/dx
or
cos (sin x) * dz/dx
but dz/dx is cos x
so
cos (sin x) * cos x
then we have
d/dx [ sin z }
which is
cos z * dz/dx
or
cos (sin x) * dz/dx
but dz/dx is cos x
so
cos (sin x) * cos x