Differentitate y = e^x^2 -^5^x +^4

Question

so far i have
dy/dx = 2x e^(x^2) - 5^(x)* ln 5 +

can you help with the rest?

Answer 1

Nope.

y=e^u -5^z I don't understand the rest.
y'=ue^u u' - ln5 * z'
where u' would be 2x and z' would be 1

Answer 2

See
http://www.jiskha.com/display.cgi?id=1245868785