Ahhh, you might recognize that
cos^2 x - sin^2 x = cos 2x
so y=sin^2(x)- cos^2(x)
= - cos 2x
dy/dx = 2sin 2x or 4sinxcosx
If you don't see that identity right away, then
dy/dx = 2(sinx)cosx - 2cosx(-sinx)
= 4sinxcosx or 2sin(2x)
differentiate:
y=sin^2(x)- cos^2(x)
I have this:
y'= 2cosx + 2sinx
What do i do next??
2 answers
Oh! Thank you so much! I completely forget about the double angle identity!!! :)
THANKS!!!
THANKS!!!