Differentiate x-3+3tanx

5 answers

To differentiate the expression x-3+3tan(x), we will use the sum/difference rule and the chain rule.

The derivative of x with respect to x is 1.
The derivative of -3 with respect to x is 0 (since it is a constant).
The derivative of 3tan(x) with respect to x requires the use of the chain rule.

Recall that the derivative of tan(x) with respect to x is sec^2(x).

Using the chain rule, the derivative of 3tan(x) with respect to x is:
3 * sec^2(x) * (d/dx)(tan(x)).

Applying the chain rule again, we have:
3 * sec^2(x) * (d/dx)(tan(x)) = 3 * sec^2(x) * sec^2(x).

Simplifying further, we have:
3 * sec^4(x).

Therefore, the derivative of x-3+3tan(x) with respect to x is:
1 + 0 + 3 * sec^4(x).

So, the final answer is:
1 + 3 * sec^4(x).
1+3/cos(x)^2
My apologies for the previous response. Let's differentiate the expression x-3+3tan(x) correctly.

The derivative of x with respect to x is 1.
The derivative of -3 with respect to x is 0 (since it is a constant).
The derivative of 3tan(x) with respect to x requires the use of the chain rule.

Recall that the derivative of tan(x) with respect to x is sec^2(x).

Using the chain rule, the derivative of 3tan(x) with respect to x is:
3 * sec^2(x) * (d/dx)(tan(x)).

Applying the chain rule again, we have:
3 * sec^2(x) * (d/dx)(tan(x)) = 3 * sec^2(x) * sec^2(x).

Simplifying, we have:
3 * sec^4(x).

Therefore, the derivative of x-3+3tan(x) with respect to x is:
1 + 0 + 3 * sec^4(x).

So, the final answer is:
1 + 3 * sec^4(x).
boy, you missed it twice!
y = x-3+3tan(x)
y' = 1 + 3sec^2(x)
no powers or chain rule involved.
You are correct, and I apologize for the repeated errors.

The derivative of x with respect to x is 1.
The derivative of -3 with respect to x is 0 (since it is a constant).
The derivative of tan(x) with respect to x is sec^2(x).

Therefore, the derivative of x-3+3tan(x) with respect to x is:
1 + 3sec^2(x).

I apologize for the confusion caused by my previous incorrect responses. Thank you for pointing it out.
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