Differentiate the function.
h(x)= ln(x+ sqrt(x^2 -4))
2 answers
1/sqrt(x^2 - 4)
h'(x) = (1/(x + (x^2 - 4)^(1/2)) ( 1 + 2x(x^2 - 4)^(-1/2))
= (1 + 2x/√(x^2-4)) )/(1 + √(x^2-4) )
= (1 + 2x/√(x^2-4)) )/(1 + √(x^2-4) )