Differentiate the function.
g(u) = sqrt(2)u+sqrt(7u)
g'(u)=?
2 answers
Can somebody get me started maybe with the first two steps and then from there Ill try finishing it and then come back on and post the answer I get.
when a is a constant, g'(au) = a g'
You know that if
y=2x, y'=2(1)
y=3x^7, y' = 3(7x^6)
The constant is just a multiplier, and carries through.
So, what you have is
g = √2 u + √7√u
You know that if
y=2x, y'=2(1)
y=3x^7, y' = 3(7x^6)
The constant is just a multiplier, and carries through.
So, what you have is
g = √2 u + √7√u
1 answer